Two resistors with resistance 100 Ω and 4 700 Ω, respectively, are connected in parallel in a

Question

circuit. The total resistance of the circuit is:

Answer 1

To find the total resistance of resistors connected in parallel, we use the formula:

1/RT = 1/R1 + 1/R2 + 1/R3 + ...

Where RT is the total resistance and R1, R2, R3, ... are the individual resistances.

In this case, we have two resistors connected in parallel with resistances of 100 Ω and 4700 Ω respectively. Plugging these values into the formula, we get:

1/RT = 1/100 + 1/4700

To simplify this equation, we can take the LCD (least common denominator) of 100 and 4700, which is 100.

1/RT = 1/100 + 1/4700 * 100/100

1/RT = 1/100 + 100/470000

1/RT = (4700 + 100)/470000

1/RT = 4800/470000

To isolate RT, we can take the reciprocal of both sides:

RT/1 = 470000/4800

RT = 470000/4800

Simplifying this expression, we get:

RT = 97.92 Ω

Therefore, the total resistance of the circuit is approximately 97.92 Ω.