Asked by Bill
Solve for t:
y=vt+(1/2)gt^2
y=vt+(1/2)gt^2
Answers
Answered by
bobpursley
put it in quadratic form...
gt^2+2vt-y=0
t= (-2v+-sqrt(4v^2+4gy))/2g
gt^2+2vt-y=0
t= (-2v+-sqrt(4v^2+4gy))/2g
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