The balanced chemical equation for the reaction is:
H2SO4 + 2 KOH → K2SO4 + 2 H2O
From the equation, we can see that 1 mole of H2SO4 reacts with 2 moles of KOH to produce 1 mole of K2SO4 and 2 moles of H2O.
To calculate the values of X and Y, we need to use the stoichiometry of the reaction. Let's assume we have 'n' moles of H2SO4 and '25n' moles of KOH.
According to the balanced equation, the ratio of moles between H2SO4 and KOH is 1:2. Therefore, 'n' moles of H2SO4 will react with '2n' moles of KOH.
So, if 'n' moles of H2SO4 react, '2n' moles of KOH will react.
From the equation, it can be seen that the ratio between moles of H2SO4 and moles of H2O is 1:2. Therefore, 'n' moles of H2SO4 will produce '2n' moles of H2O.
Similarly, the ratio between moles of KOH and moles of K2SO4 is 2:1. Therefore, '2n' moles of KOH will produce 'n' moles of K2SO4.
So, the values of X and Y are:
X = 2n
Y = n
H2OSO4+XKOH K2SO4+YH2 with the calculation and formula for solving X and Y
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