(5^2)^3 = 5^(2*3) = 5^6 = 15625
-(10x^6)^2 = -(10^2)*(x^6)^2 = -(100)*(x^12) = -100x^12
(2x^3)^4 = (2^4)*(x^3)^4 = (16)*(x^12) = 16x^12
(-8x^9)^2 = (-8^2)*(x^9)^2 = (64)*(x^18) = 64x^18
((x-2)^5)^2 = (x-2)^(5*2) = (x-2)^10
No, you cannot distribute the exponent, 2, over the subtraction.
5 Problems - SHOW ALL WORK!
(5^2)^3=
-(10x^6)^2
(2x^3)^4
(-8x^9)^2
((x-2)^5)^2 Can you distribute the exponent, 2, over the subtraction?
1 answer