The correct answer is:
Start Fraction 1 over 5 to the power of 22 baseline end fraction
Which of the following is an equivalent expression to 59⋅5−13 with only positive exponents that has been generated by applying the Properties of Integer Exponents?(1 point) Responses 154 Start Fraction 1 over 5 superscript 4 baseline end fraction 595−13 Start Fraction 5 superscript 9 baseline over 5 superscript negative 13 baseline End Fraction 1522 Start Fraction 1 over 5 superscript 22 baseline end fraction 54
1 answer