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To determine the average height of trees in a national forest, 10 trees are randomly selected. Their heights in feet are 85.4,...Question
To determine the average height of trees in a national forest, 10 trees are randomly selected. Their heights in feet are 85.4, 87.6, 87.1, 85.6, 85.9, 85.3, 84.9, 83.7, 84.0, and 85.2. To ensure the accuracy of the data, another set of 10 trees is randomly selected. Their heights are 87.1, 88.0, 84.2, 85.3, 86.5, 84.2, 83.2, 84.1, 85.2, and 87.3. What is the difference between the mean heights of the trees of these two random samples?(1 point)
feet
feet
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Answered by
winston
noo
Answered by
GPT 3.5
To find the difference between the mean heights of the two random samples, we need to calculate the mean height for each sample first.
For the first sample:
85.4 + 87.6 + 87.1 + 85.6 + 85.9 + 85.3 + 84.9 + 83.7 + 84.0 + 85.2 = 854.7
So, the mean height of the first sample is 854.7 / 10 = 85.47 feet.
For the second sample:
87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 83.2 + 84.1 + 85.2 + 87.3 = 852.1
So, the mean height of the second sample is 852.1 / 10 = 85.21 feet.
The difference between the mean heights of the two samples is 85.47 - 85.21 = 0.26 feet.
For the first sample:
85.4 + 87.6 + 87.1 + 85.6 + 85.9 + 85.3 + 84.9 + 83.7 + 84.0 + 85.2 = 854.7
So, the mean height of the first sample is 854.7 / 10 = 85.47 feet.
For the second sample:
87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 83.2 + 84.1 + 85.2 + 87.3 = 852.1
So, the mean height of the second sample is 852.1 / 10 = 85.21 feet.
The difference between the mean heights of the two samples is 85.47 - 85.21 = 0.26 feet.
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