Use the image to answer the question.
An illustration shows two sets of dot plots. One is titled Weight in Pounds, Cats and the other is Weight in Pounds, Small Dogs. The plots are shown as an abacus-like representation with dots in a vertical row over each number on a number line. For Cats, a number line with arrows on both ends ranges from 9 to 13 in increments of 1. There is 1 dot above 9, 2 dots above 10, 4 dots above 11, 2 dots above 12, and one dot above 13. For Small Dogs, a number line with arrows on both ends ranges from 8 to 15 in increments of 1. There is 1 dot above 8, 2 dots above 9, 4 dots above 10, 2 dots above 11, 2 dots above 12, 2 dots above 13, 1 dot above 14, and 1 dot above 15.
The dot plots show the weights of randomly selected cats and small dogs in different households. Based on an informal assessment of the visual overlap of these distributions, which animal has the least variability in their weights? Why?
(1 point)
Responses
Cats, because the range of their weights is less than that of small dogs.
Cats, because the range of their weights is less than that of small dogs.
Small dogs, because the range of their weights is less than that of cats.
Small dogs, because the range of their weights is less than that of cats.
Small dogs, because the range of their weights is greater than that of cats.
Small dogs, because the range of their weights is greater than that of cats.
Cats, because the range of their weights is greater than that of small dogs.
Cats, because the range of their weights is greater than that of small dogs.
13 answers
An illustration shows two sets of dot plots. One is titled Weight in Pounds, Cats and the other is Weight in Pounds, Small Dogs. The plots are shown as an abacus-like representation with dots in a vertical row over each number on a number line. For Cats, a number line with arrows on both ends ranges from 9 to 13 in increments of 1. There is 1 dot above 9, 2 dots above 10, 4 dots above 11, 2 dots above 12, and one dot above 13. For Small Dogs, a number line with arrows on both ends ranges from 8 to 15 in increments of 1. There is 1 dot above 8, 2 dots above 9, 4 dots above 10, 2 dots above 11, 2 dots above 12, 2 dots above 13, 1 dot above 14, and 1 dot above 15.
The dot plots show the weights of randomly selected cats and small dogs in different households. What is the difference between the modal weights of cats and small dogs?
(1 point)
Responses
0.13 pounds
0.13 pounds
3 pounds
3 pounds
The modal weights are the same for cats and small dogs.
The modal weights are the same for cats and small dogs.
1 pound
Class 1: 6, 8, 10, 11, 14, 4, 5, 8, 2, 7, 7, 5, 10, 12, 11
Class 2: 6, 4, 5, 6, 7, 8, 12, 9, 10, 11, 5, 8, 7, 4, 10
(1 point)
Responses
Class 2 has a higher median than Class 1 by 0.5 mile.
Class 2 has a higher median than Class 1 by 0.5 mile.
Class 1 has a higher median than Class 2 by 1 mile.
Class 1 has a higher median than Class 2 by 1 mile.
Class 2 has a higher median than Class 1 by 1 mile.
Class 2 has a higher median than Class 1 by 1 mile.
Class 1 has a higher median than Class 2 by 0.5 mile.
Class 1: 2, 4, 5, 5, 6, 7, 7, 8, 8, 10, 10, 11, 11, 12, 14
Class 2: 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 10, 10, 11, 12
Since both data sets have an odd number of values, the median is the middle value.
For Class 1, the median is 8.
For Class 2, the median is 7.
The difference between the medians is 8 - 7 = 1.
Therefore, Class 1 has a higher median than Class 2 by 1 mile.
Student Group A: 56, 14, 26, 28, 29, 45, 32, 80, 3, 10
Student Group B: 27, 24, 18, 19, 5, 16, 22, 10, 6, 20
Which of the following statements about these data sets is false?
(1 point)
Responses
The mean time taken by Group A is higher than that of Group B.
The mean time taken by Group A is higher than that of Group B.
The amount of variability of the time taken by Group A to thread a needle is higher than the amount of variability of the time taken by Group B.
The amount of variability of the time taken by Group A to thread a needle is higher than the amount of variability of the time taken by Group B.
The ranges of the time taken by Group A and Group B are the same.
The ranges of the time taken by Group A and Group B are the same.
The median time taken by members of Group A to thread a needle is higher than that of members of Group B.
This statement is false. The range of a data set is the difference between the maximum and minimum values.
For Group A:
Minimum value: 3
Maximum value: 80
Range: 80 - 3 = 77
For Group B:
Minimum value: 5
Maximum value: 27
Range: 27 - 5 = 22
Therefore, the ranges of the time taken by Group A and Group B are not the same.
The median time taken by members of Group A to thread a needle is higher than that of members of Group B.
The median time taken by Group A is 28.5, while the median time taken by Group B is 18. Therefore, the median time taken by members of Group A is not higher than that of members of Group B.
The mean time taken by Group A is higher than that of Group B.
The mean time taken by Group A is approximately 33.6 seconds, while the mean time taken by Group B is approximately 16.7 seconds. Therefore, the mean time taken by Group A is not higher than that of Group B.
Fertilizer A: 27, 20, 16, 18, 22, 19, 23, 21, 17, 19
Fertilizer B: 28, 19, 18, 21, 24, 20, 25, 27, 29, 21
(1 point)
Responses
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
Fertilizers A and B are equally effective, because the ranges of the weights of the potatoes are the same.
Fertilizers A and B are equally effective, because the ranges of the weights of the potatoes are the same.
Fertilizers A and B are both ineffective, because there is no difference in the ranges of the weights of the potatoes.
Fertilizers A and B are both ineffective, because there is no difference in the ranges of the weights of the potatoes.
Fertilizer A is generally more effective, because the mean and median weights of the potatoes treated with it are higher.
Mean weight for Fertilizer A: (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) / 10 = 202 / 10 = 20.2 kilograms
Mean weight for Fertilizer B: (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) / 10 = 232 / 10 = 23.2 kilograms
Median weight for Fertilizer A: 19 kilograms
Median weight for Fertilizer B: 21 kilograms
Based on the mean and median weights, Fertilizer B is generally more effective as it has higher mean and median weights of the potatoes treated with it. Therefore, the correct statement is:
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.