Asked by Amanda
At what altitude above the Earth's surface would your weight be three-fourths of what it is at the Earth's surface? Assume re = 6.371 10^3 km.
Answers
Answered by
MathMate
Based on Newton's law of universal gravitation,
F=GMm/r²
which means that the weight would be inversely proportional to the square of the distance from the centre of the Earth.
If H is the altitude when the weight becomes 3/4 of what's on the surface, then
(re/(re+H))^2=3/4
Solve for H.
F=GMm/r²
which means that the weight would be inversely proportional to the square of the distance from the centre of the Earth.
If H is the altitude when the weight becomes 3/4 of what's on the surface, then
(re/(re+H))^2=3/4
Solve for H.
Answered by
Lindsey
Solved out for H:
(6371/sqrt(3/4)) - 6371 = H
for other fractions just plug in where 3/4's is.
Hope this helps!
(6371/sqrt(3/4)) - 6371 = H
for other fractions just plug in where 3/4's is.
Hope this helps!
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