Question
A particular sprinter reaches a horizontal acceleration of 13.3 m/s2 out of the starting block. The starting block is tilted such that the vertical component of the force which the starting block exerts on the sprinter compensates for the weight of the sprinter, leading to a zero vertical acceleration. What is the magnitude of the force with which the 64 kg sprinter pushes against the starting block?
Answers
The vertical force component applied by the block is M g. The horizontal component is M a, where a = 13.3 m/s^2.
g = 9.8 m/s^2
The magnitude of the force is
F = M sqrt(a^2 + g^2)
Use the M = 64 kg and compute F
g = 9.8 m/s^2
The magnitude of the force is
F = M sqrt(a^2 + g^2)
Use the M = 64 kg and compute F
Related Questions
ok so I have a question
At the instatn a race began, a 57-kg sprinter was found to exert a force...
At the instant a race began, a 74.0 kg sprinter exerted a force of 850 N on the starting block at a...
At the instant a race began, a 89.1 kg sprinter exerted a force of 710 N on the starting block in...
A 67.5 kg sprinter exerts a force of 775 N on the starting block which makes a 20 degree angle to th...