Which of the first 10 natural numbers is NOT a solution of 5x−1≠9 ?(1 point)
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To find the number that is not a solution of the equation 5x - 1 ≠ 9, we can substitute each of the first 10 natural numbers (1, 2, 3, 4, 5, 6, 7, 8, 9, 10) into the equation and check whether the inequality holds.
Substituting 1: 5(1) - 1 = 5 - 1 = 4 ≠ 9.
Substituting 2: 5(2) - 1 = 10 - 1 = 9 ≠ 9.
Substituting 3: 5(3) - 1 = 15 - 1 = 14 ≠ 9.
Substituting 4: 5(4) - 1 = 20 - 1 = 19 ≠ 9.
Substituting 5: 5(5) - 1 = 25 - 1 = 24 ≠ 9.
Substituting 6: 5(6) - 1 = 30 - 1 = 29 ≠ 9.
Substituting 7: 5(7) - 1 = 35 - 1 = 34 ≠ 9.
Substituting 8: 5(8) - 1 = 40 - 1 = 39 ≠ 9.
Substituting 9: 5(9) - 1 = 45 - 1 = 44 ≠ 9.
Substituting 10: 5(10) - 1 = 50 - 1 = 49 ≠ 9.
From the above calculations, we can observe that none of the first 10 natural numbers satisfy the inequality 5x - 1 ≠ 9. Therefore, all the first 10 natural numbers (1, 2, 3, 4, 5, 6, 7, 8, 9, and 10) are not solutions of the equation.
Substituting 1: 5(1) - 1 = 5 - 1 = 4 ≠ 9.
Substituting 2: 5(2) - 1 = 10 - 1 = 9 ≠ 9.
Substituting 3: 5(3) - 1 = 15 - 1 = 14 ≠ 9.
Substituting 4: 5(4) - 1 = 20 - 1 = 19 ≠ 9.
Substituting 5: 5(5) - 1 = 25 - 1 = 24 ≠ 9.
Substituting 6: 5(6) - 1 = 30 - 1 = 29 ≠ 9.
Substituting 7: 5(7) - 1 = 35 - 1 = 34 ≠ 9.
Substituting 8: 5(8) - 1 = 40 - 1 = 39 ≠ 9.
Substituting 9: 5(9) - 1 = 45 - 1 = 44 ≠ 9.
Substituting 10: 5(10) - 1 = 50 - 1 = 49 ≠ 9.
From the above calculations, we can observe that none of the first 10 natural numbers satisfy the inequality 5x - 1 ≠ 9. Therefore, all the first 10 natural numbers (1, 2, 3, 4, 5, 6, 7, 8, 9, and 10) are not solutions of the equation.
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