The equation of a line can be expressed in slope-intercept form, which is:
y = mx + b
where m is the slope and b is the y-intercept.
Given that the slope is -1/6 and the point (-6,-3) lies on the line, we can substitute these values into the equation to find the y-intercept.
-3 = (-1/6)(-6) + b
-3 = 1 + b
b = -4
Therefore, the equation of the line is:
y = (-1/6)x - 4
What is the equation of the line that passes through the point left bracket, minus, 6, comma, minus, 3, right bracket(−6,−3) and has a slope of minus, one sixth−
6
1
?
1 answer