a) The limiting reactant is octane (C8H18).
b) 18 moles of water are formed, so 18 x 18.015 g/mol = 324.27 g of water are formed.
c) 1510 g of oxygen are consumed.
d) 255 g of octane are left un-reacted.
255 grams of octane and 1510 grams of oxygen gas are present at the beginning of reaction that goes to completion and forms carbon dioxide and water according to the following equation. 2C8H18 (l) + 2502 (g) → 16CO2 (g) + 18H2O (g) (3pts.) a) What is the limiting reactant? b) How many grams of water are formed? c) How many grams of excess reactant are consumed? d) How many grams of excess reactant are left un-reacted?
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