Asked by tai

the 6th grade has 5 days to sell tickets to a talent show. The students predict that each day they will sell 10 fewer tickets than the day before. How many must they sell on the first day if they want to sell 200 tickets?

--- do I divide 10 by 200 that would not make sense

please try to help me thanks
Answered by Reiny
You are probably studying arithmetic sequences and series

let the first term be a
common difference is -10
and the number of terms is 5
S<sub>n</sub> = (n/2)[2a + (n-1)d]
200 = (5/2)[2a + 4(-10)]
400 = 5[2a - 40]
400 = 10a - 200
600 = 10a
a = 60

So on the first day they must sell 60 tickets

check: 60 + 50 + 40 + 30 + 20 =
Answered by M Bhatt
assume that they will sell x tickets on the first day.

Sale on second day will be x-10
third day x-20
fourth day x-30
fifth day x-40

if we add them all up
x+x-10+x-20+x-30+x-40=200
5x-100=2==
5x=300
x=60

so they have to sell 60 on the first day
50 on the second
40 on the third
30 on the fourth
and 20 on fifth day.

Answered by arny
find the difference using model subtraction with renaming
Answered by Magic
The product of a number and seven increased by twenty-three is equal to one hundred seven.
Answered by quandariusmoran
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