solve for b

3 (b + a) + r

1 answer

To solve for b, we should isolate it on one side of the equation.

Starting with the equation:
3(b + a) + r

Distribute the 3:
3b + 3a + r

Subtract 3a and r from both sides:
3b = -3a - r

Divide both sides by 3:
b = (-3a - r)/3

So the solution for b is:
b = (-3a - r)/3