Question
A chain consisting of 5 links, each of mass 0.100kg is lifted vertically with a constant acceleration of 2.50 m/s^2.
Calculate the force that link 2 exerts of link 1.
Calculate the force that link 2 exerts of link 1.
Answers
The force will be the total weight the link supports (Σmg) + the acceleration of 2.5 m/s² multiplied by the total mass (Σm) it supports.
F = Σm(g+a)
F = Σm(g+a)
1.23
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