Efficiency = output work / input work x 100
Efficiency = 300 joules / 1200 joules x 100
Efficiency = 0.25 x 100
Efficiency = 25%
Therefore, the efficiency of the ramp is 25%. The answer is option A.
Tito and Michael put 1200 joules of work into pushing a box up a ramp, but only 300 joules of work is output for moving the box. What is the efficiency of the ramp?
Efficiency = output work/input work x 100
A. 25 %
B. 360,000 %
C. .25 %
D. 4 %
1 answer