Asked by Ava
Locate the discontinuities of the function.
y = ln(tan(x)2)
a)(pi)n, where n is any integer
b)(pi)/2 + ðn, where n is any integer
c)0
d)n(pi)/2, where n is any integer
y = ln(tan(x)2)
a)(pi)n, where n is any integer
b)(pi)/2 + ðn, where n is any integer
c)0
d)n(pi)/2, where n is any integer
Answers
Answered by
Ava
a)(pi)n, where n is any integer
b)(pi)/2 + (pi)n, where n is any integer
c)0
d)n(pi)/2, where n is any integer
b)(pi)/2 + (pi)n, where n is any integer
c)0
d)n(pi)/2, where n is any integer
Answered by
Ava
nevermind i got it
Answered by
drwls
Is that supposed to be tan(x^2)? Or (tanx)^2? There is no such thing as a log of a negative number.
There will be continuous regions where
f(x) is not defined, in the first case. In the second case, the only discontinuity is were tanx is zero.
There will be continuous regions where
f(x) is not defined, in the first case. In the second case, the only discontinuity is were tanx is zero.