Question
In the diagram, m∠A=(4x−10)° and m∠D=(2x+22)° . What is the measure of ∠D ? (1 point)
whats the answer
whats the answer
Answers
Answer
wrong
Answer
still wwrong
Answer
In the diagram, m∠A=(4x−10)° and m∠D=(2x+22)° . What is the measure of ∠D ? (1 point)
(and no its not 2x+22)
(and no its not 2x+22)
Answer
WWRROONGG
Answered by
GPT 3.5
The measure of ∠D is 2x+22 degrees.
Answered by
GPT 3.5
Apologies for the wrong response.
To find the measure of ∠D, we need to equate it to the given expression, which is (2x+22)°. So, the measure of ∠D is 2x+22 degrees.
To find the measure of ∠D, we need to equate it to the given expression, which is (2x+22)°. So, the measure of ∠D is 2x+22 degrees.
Answered by
GPT 3.5
Apologies for the repeated error.
To find the measure of ∠D, we need to use the given information that m∠D=(2x+22)°. However, since no further information or relationships are provided in the question or diagram, we cannot determine the specific value of x or the measure of ∠D.
To find the measure of ∠D, we need to use the given information that m∠D=(2x+22)°. However, since no further information or relationships are provided in the question or diagram, we cannot determine the specific value of x or the measure of ∠D.
Answered by
GPT 3.5
Apologies for the confusion and incorrect responses.
To find the measure of ∠D, we can equate it to the given expression m∠D = (2x + 22)°.
Therefore, the measure of ∠D is 2x + 22 degrees.
To find the measure of ∠D, we can equate it to the given expression m∠D = (2x + 22)°.
Therefore, the measure of ∠D is 2x + 22 degrees.
Answered by
GPT 3.5
Apologies for the repeated error.
Since the given information states that m∠D = (2x + 22)°, the measure of ∠D is indeed 2x + 22 degrees.
If you have any additional information or context regarding the diagram, please provide it, and I'll be happy to assist you further.
Since the given information states that m∠D = (2x + 22)°, the measure of ∠D is indeed 2x + 22 degrees.
If you have any additional information or context regarding the diagram, please provide it, and I'll be happy to assist you further.
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