Asked by lol
Convert the equation from vertex form to standard form y = - 4 * (x + 5) ^ 2 - 3; y = 16x ^ 2 + 160x + 412; y = - 4x ^ 2 - 40x - 103; y = 16x ^ 2 + 160x + 397; y = - 4x ^ 2 - 25x - 3
Answers
Answered by
lol
Are you sure
Answered by
GPT 3.5
To convert the equation from vertex form to standard form, we need to expand the equation and simplify it.
Let's take the first equation as an example:
y = -4 * (x + 5) ^ 2 - 3
First, we need to expand the square:
y = -4 * (x^2 + 10x + 25) - 3
Next, distribute the -4 to each term inside the parentheses:
y = -4x^2 - 40x - 100 - 3
Combine the constant terms:
y = -4x^2 - 40x - 103
So, the equation in standard form is y = -4x^2 - 40x - 103.
Let's take the first equation as an example:
y = -4 * (x + 5) ^ 2 - 3
First, we need to expand the square:
y = -4 * (x^2 + 10x + 25) - 3
Next, distribute the -4 to each term inside the parentheses:
y = -4x^2 - 40x - 100 - 3
Combine the constant terms:
y = -4x^2 - 40x - 103
So, the equation in standard form is y = -4x^2 - 40x - 103.
Answered by
GPT 3.5
Apologies for the mistake in the previous response.
Let's go through the conversion process again for the first equation:
Given equation in vertex form: y = -4 * (x + 5) ^ 2 - 3
First, we need to expand the square:
y = -4 * (x^2 + 10x + 25) - 3
Next, distribute the -4 to each term inside the parentheses:
y = -4x^2 - 40x - 100 - 3
Combine the constant terms:
y = -4x^2 - 40x - 103
So, the equation in standard form is indeed y = -4x^2 - 40x - 103.
Let's go through the conversion process again for the first equation:
Given equation in vertex form: y = -4 * (x + 5) ^ 2 - 3
First, we need to expand the square:
y = -4 * (x^2 + 10x + 25) - 3
Next, distribute the -4 to each term inside the parentheses:
y = -4x^2 - 40x - 100 - 3
Combine the constant terms:
y = -4x^2 - 40x - 103
So, the equation in standard form is indeed y = -4x^2 - 40x - 103.