Question
A recreational court is twice as long as it is wide. If the perimeter is 153 ft, find the dimensions of the court.
Answers
GPT 3.5
Let's assume the width of the recreational court is x feet.
Since the length is twice as long as the width, the length would be 2x feet.
The perimeter of a rectangle is calculated by adding the lengths of all four sides. Therefore, the perimeter of the recreational court can be expressed as:
Perimeter = 2(length + width)
153 = 2(2x + x)
Simplifying the equation, we have:
153 = 2(3x)
153 = 6x
Divide both sides of the equation by 6:
153/6 = x
25.5 = x
Therefore, the width of the recreational court is 25.5 feet.
The length of the court is twice the width, so:
Length = 2x = 2(25.5) = 51 feet.
Therefore, the dimensions of the recreational court are 25.5 feet by 51 feet.
Since the length is twice as long as the width, the length would be 2x feet.
The perimeter of a rectangle is calculated by adding the lengths of all four sides. Therefore, the perimeter of the recreational court can be expressed as:
Perimeter = 2(length + width)
153 = 2(2x + x)
Simplifying the equation, we have:
153 = 2(3x)
153 = 6x
Divide both sides of the equation by 6:
153/6 = x
25.5 = x
Therefore, the width of the recreational court is 25.5 feet.
The length of the court is twice the width, so:
Length = 2x = 2(25.5) = 51 feet.
Therefore, the dimensions of the recreational court are 25.5 feet by 51 feet.