Asked by Allison
The centers of a 11 kg lead ball and a 70 g lead ball are separated by 8.0 cm. What gravitational force does each exert on the other?
Answers
Answered by
MathMate
Gravitaional constant, G,
= 6.67*10<sup>-11</sup> N (m/kg)²
Force
= GMm/r²
= 6.67*10<sup>-11</sup> * 11 * 0.07/0.08²
=8.0*10^(-9) N
= 6.67*10<sup>-11</sup> N (m/kg)²
Force
= GMm/r²
= 6.67*10<sup>-11</sup> * 11 * 0.07/0.08²
=8.0*10^(-9) N
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