Asked by Ann
Evaluate x and y
x^4y^2 when x = 5/6 and y = - 3/5
x^4y^2 when x = 5/6 and y = - 3/5
Answers
Answered by
DrBob222
(5/6)^4*(-3/5)^2 =
(5^4/6^4)*(-3^2/5^2) =
(625/1296)*(9/25) = 25/144
[Note 25 divided into 625, 25 times. 9 divided into 1296, 144 times.]
(5^4/6^4)*(-3^2/5^2) =
(625/1296)*(9/25) = 25/144
[Note 25 divided into 625, 25 times. 9 divided into 1296, 144 times.]
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