E = IR
120 = 0.5R
Solve for R.
A light bulb, after it has reached its operation temperature, is connected across a potential difference of 120V while 0.5A of current passses through it. What is the resistance of the light bulb?
2 answers
120/0.5 = 0.5R/0.5
= 240 ohms
= 240 ohms