Asked by LSM
f(x)=4-2(x-6)^1/3 evaluate when f(x)=5
so I did this:
5=4-2(x-6)^1/3
1=-2(x-6)^1/3
(-1/2)=(x-6)^1/3
How do I get rid of the exponent 1/3? I am stumped.
so I did this:
5=4-2(x-6)^1/3
1=-2(x-6)^1/3
(-1/2)=(x-6)^1/3
How do I get rid of the exponent 1/3? I am stumped.
Answers
Answered by
Reiny
cube both sides
(an exponent of 1/3 means cube root, so what is the inverse of taking the cube root ?)
(-1/2)^3=[(x-6)^1/3]^3
-1/8 = x-6
x = 6-1/8
x = 47/8
(an exponent of 1/3 means cube root, so what is the inverse of taking the cube root ?)
(-1/2)^3=[(x-6)^1/3]^3
-1/8 = x-6
x = 6-1/8
x = 47/8
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.