Asked by Jasmine
When 0.100 mol of carbon is burned in a close vessel with 8.00g of oxygen, how many grams of carbon dioxide can form? Which reactant is in excess, and how many grams of it remain after the reaction?
Answers
Answered by
DrBob222
C + O2 ==> CO2
You have 0.1 mol C.
Convert 8 g O2 to moles. 8/32 = 0.25 mol.
0.1 mole C can form 0.1 mole CO2
0.25 mole O2 can form 0.25 mole CO2.
In limiting reagent problems, the smaller number is ALWAYS the correct one to choose. So C is the limiting reagent and will react completely. Some oxygen will remain unreacted.
g CO2 formed = 0.1 mole CO2 x molar mass CO2 = 0.1 x 44 = ?? grams CO2.
How much oxygen remains. First, determine how much oxygen is used.
0.1 mols CO2 will use 0.1 mole O2 and 0.1 mole O2 is 0.1 x 32 = 3.2 grams.
We had 8 g initially; therefore, the amount remaining is 8.0 - 3.2 = ?? grams. Check my work carefully. It's getting late here.
You have 0.1 mol C.
Convert 8 g O2 to moles. 8/32 = 0.25 mol.
0.1 mole C can form 0.1 mole CO2
0.25 mole O2 can form 0.25 mole CO2.
In limiting reagent problems, the smaller number is ALWAYS the correct one to choose. So C is the limiting reagent and will react completely. Some oxygen will remain unreacted.
g CO2 formed = 0.1 mole CO2 x molar mass CO2 = 0.1 x 44 = ?? grams CO2.
How much oxygen remains. First, determine how much oxygen is used.
0.1 mols CO2 will use 0.1 mole O2 and 0.1 mole O2 is 0.1 x 32 = 3.2 grams.
We had 8 g initially; therefore, the amount remaining is 8.0 - 3.2 = ?? grams. Check my work carefully. It's getting late here.
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