To find the volume V of the decorative bowl, we need to use the formula V = (1/2)(4/3)πr^3, where r is the radius of the hemisphere. Since the bowl is in the shape of a hemisphere, its radius is half the diameter of the bowl.
Given that the diameter of the bowl is 11 cm, we can find the radius by dividing the diameter by 2:
r = 11 cm / 2 = 5.5 cm.
Now we can substitute the value of the radius into the formula and calculate the volume V:
V = (1/2)(4/3)(3.14)(5.5 cm)^3
V = (2/3)(3.14)(166.375 cm^3)
V = (2/3)(523.9375 cm^3)
V ≈ 349.29 cm^3.
Rounding to the nearest whole number, the volume of the decorative bowl is approximately 349 cm^3.
A decorative bowl is in the shape of a hemisphere . What is the volume of the bowl? Use π=3.14 and round your answer to the nearest whole. Formula: V=1/2 . 4/3 πr m^3. 11 cm
4 answers
Wrong
To find the volume V of the decorative bowl, we need to use the formula V = (1/2)(4/3)πr^3, where r is the radius of the hemisphere.
Given that the radius of the hemisphere is 11 cm, we can substitute this value into the formula and calculate the volume V:
V = (1/2)(4/3)(3.14)(11 cm)^3
V = (1/2)(4/3)(3.14)(1331 cm^3)
V = (2/3)(3.14)(1331 cm^3)
V = (2/3)(4182.14 cm^3)
V = 2788.09 cm^3
Rounding to the nearest whole number, the volume of the decorative bowl is approximately 2788 cm^3.
Given that the radius of the hemisphere is 11 cm, we can substitute this value into the formula and calculate the volume V:
V = (1/2)(4/3)(3.14)(11 cm)^3
V = (1/2)(4/3)(3.14)(1331 cm^3)
V = (2/3)(3.14)(1331 cm^3)
V = (2/3)(4182.14 cm^3)
V = 2788.09 cm^3
Rounding to the nearest whole number, the volume of the decorative bowl is approximately 2788 cm^3.
same quistion but 11cm is in the radius center
1 answer