I am trying to answer my questions for thermal decomposition of malachite lab. I have moles of malachite in 1g= 0.0045

Question

moles of Cuo produced= 0.0009
ratio of moles of Cuo produced per moles of malachite decomposed=0.0045/0.0009=5.1

the balanced euation = CuCo3*Cu9OH)2 -----> 2Cuo+Co2+H2O

I am stuck on the next questions:
4.) Predict the mas of Cuo expected to result fron the decomposition of the malachite, based on the balanced equation

5.) Compare the mass obtained from the mass predicted, and discuss reasons for any discrepancy

6.) Suggest a way to demonstrated that Co2 is a product of the reaction

Answer 1

You really need to watch the caps and typing. Co and CO are NOT the same thing

I am stuck on the next questions:
4.) Predict the mas of Cuo expected to result fron the decomposition of the malachite, based on the balanced equation.
You have the moles CuO and that is correct. grams CuO = moles CuO x molar mass CuO.

5.) Compare the mass obtained from the mass predicted, and discuss reasons for any discrepancy
You will need to follow up on this. The answer depends upon how much CuO was obtained in the experiment

6.) Suggest a way to demonstrated that Co2 is a product of the reaction

It's CO2 and not Co2. CO2 is carbon dioxide. One way to test for CO2 is to allow the gas to come in contact with a film of Ca(OH)2 solution. This is usually done by dipping a wire in which the end has been bent into a circle. The inside of the wire circle then holds a small film of the solution. It turns white upon the addition of CO2. SO2 and SO3 do the same thing; however, they have an unpleasant odor whereas CO2 is odorless.