18.
x^2+2(3x-2)=x^2+6x-4
x^2 + 6x - 4 = x^2 + 6x - 4
clearly an identity, that is, the equation is true for all values of x
15.
(4x+1)-2x=2(x+2)
4x + 1 - 2x = 2x + 4
2x + 1 = 2x = 4
1 = 4 , Oh really?
This equation has no solution.
It is neither an identity nor "conditional equation".
I'm trying to learn the difference between conditional and identity equations. Can you please check my work??
12). 3(x+2)=5x+4. I said conditional because on the one side x needed to equal negative two while on the other, it needed to equal -.8.
15). (4x+1)-2x=2(x+2) I said identity.
18). x^2+2(3x-2)=x^2+6x-4. I said Conditional, out of more of a guess than actual information. I reduced it to x^2+x=.60, but I was unsure how to figure out the left side of the reduction. Could you explain this??
Thanks!!!
1 answer