Question
Knowing the given conditions, write the equation of the circle. Center at (4,2) and the circle passes through (-1,-1).
Please help!
Please help!
Answers
I will assume you know that the equation of a circle with centre (h,k) and radius r is
(x-h)^2 + (y-k)^2 = r^2
then (x-4)^2 + (y-2)^2 = r^2
but (-1,-1) lies on it, so
(-1-4)^2 + (-1-2)^2 = r^2
r^2 = 34
(x-4)^2 + (y-2)^2 = 34
(x-h)^2 + (y-k)^2 = r^2
then (x-4)^2 + (y-2)^2 = r^2
but (-1,-1) lies on it, so
(-1-4)^2 + (-1-2)^2 = r^2
r^2 = 34
(x-4)^2 + (y-2)^2 = 34
Thanks!
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