To graph the equation −8 + x = 4y − 16, first we rearrange the equation to get it in slope-intercept form, y = mx + b. We can do this by isolating the y-variable:
−8 + x + 16 = 4y
x + 8 = 4y
y = (x + 8)/4
y = (1/4)x + 2
Now we can see that the slope (m) is 1/4 and the y-intercept (b) is 2.
To graph this equation, we start by plotting the y-intercept, which is the point (0, 2) on the y-axis.
Then, using the slope of 1/4, we can determine a second point by moving up one unit and to the right four units from the y-intercept. This gives us the point (4, 3).
Plot these two points and draw a straight line passing through them. The line represents the graph of the equation −8 + x = 4y − 16.
The graph of the equation is a straight line with a slope of 1/4 and a y-intercept of (0, 2).
Graph −8+x=4y−16.
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