To graph the equation y+6=45(x+3), we need to rearrange it into the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
Given equation: y+6=45(x+3)
Simplify it: y + 6 = 45x + 135
Now, isolate the y variable: y = 45x + 135 - 6
Simplify further: y = 45x + 129
So, the equation is now in slope-intercept form with a slope of 45 and a y-intercept of 129.
To plot the graph, we can choose any two points on the line.
Let's choose x = 0
If we substitute x = 0 into the equation y = 45x + 129, we can find the corresponding y value:
y = 45(0) + 129
y = 0 + 129
y = 129
So, our first point is (0, 129).
Now, let's choose x = -3:
If we substitute x = -3 into the equation, we get:
y = 45(-3) + 129
y = -135 + 129
y = -6
Our second point is (-3, -6).
Now we can graph the line using the line tool and plot the points (0, 129) and (-3, -6).
Graph y+6=45(x+3) using the point and slope given in the equation.
Use the line tool and select two points on the line.
1 answer
1 answer