Question

Graph ​y+6=45(x+3)​ using the point and slope given in the equation.

Use the line tool and select two points on the line.

Answer 1

To graph the equation ​y+6=45(x+3)​​, we need to rearrange it into the slope-intercept form (​y = mx + b​), where ​m​ is the slope and ​b​ is the y-intercept.

Given equation: ​y+6=45(x+3)​
Simplify it: ​y + 6 = 45x + 135
Now, isolate the ​y​ variable: ​y = 45x + 135 - 6
Simplify further: ​y = 45x + 129
So, the equation is now in slope-intercept form with a slope of 45 and a y-intercept of 129.

To plot the graph, we can choose any two points on the line.

Let's choose​ x = 0​​
If we substitute ​x = 0​​ into the equation ​y = 45x + 129​​, we can find the corresponding ​y​ value:

​y = 45(0) + 129
​y = 0 + 129
​y = 129

So, our first point is (0, 129).

Now, let's choose ​x = -3​​:
If we substitute ​x = -3​​ into the equation, we get:

​y = 45(-3) + 129
​y = -135 + 129
​y = -6

Our second point is (-3, -6).

Now we can graph the line using the line tool and plot the points (0, 129) and (-3, -6).