TOP ->--<- carp ->--<- trout ---- bottom
==75.3N=======2.29 kg ====== 3.49 kg
Total mass, M = (2.29+3.49) kg
total weight, Mg = 9.8M N
Total upward force, F = 75.3 N
net upward force, F1 = F - Mg N
Acceleration, a = F1/M
Isolate the trout of mass m, forces acting on it are its weight, mg and tension on the rope, T.
Therefore,
ma = T-mg
Solve for T since m,a,and g are known.
Jimmy has caught two fish in Yellow Creek. He has tied the line holding the 3.40 kg steelhead trout to the tail of the 2.29 kg carp. To show the fish to a friend, he lifts upward on the carp with a force of 75.3 N. What is the tension of the rope connecting the steel trout and carp?
1 answer