3y-5 (2y-4) = 62

Answer 1

Expanding the expression, we get:

3y * 2y - 3y * 4 - 5 * 2y + 5 * 4 = 62

6y^2 - 12y - 10y + 20 = 62

6y^2 - 22y + 20 = 62

6y^2 - 22y - 42 = 0

Now we can solve this quadratic equation by factoring or using the quadratic formula.