To find the value for "a" that will produce perpendicular lines, we need to find the slope of the given equation 6x - 3y = 12, and then find the negative reciprocal of that slope.
First, let's rewrite the equation 6x - 3y = 12 in slope-intercept form: y = mx + b
Subtract 6x from both sides: -3y = -6x + 12
Divide both sides by -3: y = 2x - 4
The slope of this equation is 2.
The negative reciprocal of 2 is -1/2.
Therefore, the value for "a" in the equation ax - 2y = 10 that will produce perpendicular lines is -1/2.
Given the equation 6x−3y=12 , find the value for a in the equation ax−2y=10 that will produce perpendicular lines.
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