Question

A student solved the following equation using the following steps: 4(2−3x)=x−2(2x+1)4(2−3x)=x−2(2x+1) 8−3x=x−4x−28−3x=x−4x−2 8−3x=−3x−28−3x=−3x−2 Answer: No Solution (2 points) Based on the student’s work, the equation was solved_____
correctly
incorrectly
The equation solved correctly would show that it has_____
no solution
one solution
infinitely many solution
two solution

Answer 1

Based on the student's work, the equation was solved incorrectly. The equation should have been solved correctly if it had one solution.