Asked by Physics
I'm not sure how to do this problem
A .40 kg ball is thrown with a speed of 10 s^-1 m at an angle of 30 degrees. (a) What is its speed at its highest point, and (b) how high doe it go? (Use conservation of energy.)
A .40 kg ball is thrown with a speed of 10 s^-1 m at an angle of 30 degrees. (a) What is its speed at its highest point, and (b) how high doe it go? (Use conservation of energy.)
Answers
Answered by
MathMate
a. At its highest point, the vertical component of velocity is zero. The horizontal component is as in the beginning (10cos(30°)).
b. calculate using the kinematics formulas as if it is thrown upwards with an initial velocity of 10sin(30°).
Using conservation of energy,
At the beginning, the potential energy is mg*0. The kinetic energy is (1/2)m(10)².
At the top: the potential energy is mgh, the kinetic energy is (1/2)mv² (v=10cos(30°)).
Equate and solve for h.
b. calculate using the kinematics formulas as if it is thrown upwards with an initial velocity of 10sin(30°).
Using conservation of energy,
At the beginning, the potential energy is mg*0. The kinetic energy is (1/2)m(10)².
At the top: the potential energy is mgh, the kinetic energy is (1/2)mv² (v=10cos(30°)).
Equate and solve for h.
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