Question
After selling 14 1/2 kg of flour, a shopkeeper had 5/8kg of flour left. How much flour did he have at first?
Answers
GPT 3.5
Let's call the amount of flour the shopkeeper had at first "x" kg.
After selling 14 1/2 kg, the shopkeeper had x - 14 1/2 kg left.
We know that this amount is equal to 5/8 kg.
So we can write the equation: x - 14 1/2 = 5/8.
To add 14 1/2 and 5/8, we need to find a common denominator, which is 8.
14 1/2 is equivalent to 14 4/8. So, the equation becomes: x - 14 4/8 = 5/8.
Now, we can add the fractions: x - 14 4/8 = 5/8.
To do this, we need to find a common denominator, which is 8.
So, x - 118/8 = 5/8.
Next, we can simplify the left side of the equation by subtracting the fractions:
x - 118/8 = 5/8.
Multiplying the denominator and numerator of 118/8 by 8 will give us: x - 118 = 5.
To isolate "x", we need to add 118 to both sides of the equation: x - 118 + 118 = 5 + 118.
This simplifies to: x = 123.
Therefore, the shopkeeper had 123 kg of flour at first.
After selling 14 1/2 kg, the shopkeeper had x - 14 1/2 kg left.
We know that this amount is equal to 5/8 kg.
So we can write the equation: x - 14 1/2 = 5/8.
To add 14 1/2 and 5/8, we need to find a common denominator, which is 8.
14 1/2 is equivalent to 14 4/8. So, the equation becomes: x - 14 4/8 = 5/8.
Now, we can add the fractions: x - 14 4/8 = 5/8.
To do this, we need to find a common denominator, which is 8.
So, x - 118/8 = 5/8.
Next, we can simplify the left side of the equation by subtracting the fractions:
x - 118/8 = 5/8.
Multiplying the denominator and numerator of 118/8 by 8 will give us: x - 118 = 5.
To isolate "x", we need to add 118 to both sides of the equation: x - 118 + 118 = 5 + 118.
This simplifies to: x = 123.
Therefore, the shopkeeper had 123 kg of flour at first.