We can write the relationship between x and y as follows:
x = ky + ly^2
To solve for the values of k and l, we can substitute the given values for y and x in the two given scenarios:
When y = 4, x = 52 * 8
=> 52 * 8 = 4k + 16l
=> 416 = 4k + 16l
When y = 5, x = 81
=> 81 = 5k + 25l
Now we can solve these two equations simultaneously to find the values of k and l. We can subtract the second equation from the first:
416 - 81 = (4k + 16l) - (5k + 25l)
=> 335 = -k - 9l
Next, we can solve for one variable in terms of the other. Let's solve for k in terms of l using the second equation:
k = 81 - 25l
Now we can substitute this value of k into the first equation:
335 = -(81 - 25l) - 9l
=> 335 = -81 + 9l - 9l
=> 335 = -81
=> l = -22.222
We can now substitute this value of l back into the second equation to solve for k:
81 = 5k - 25(-22.222)
=> 81 = 5k + 555.56
=> 5k = -474.56
=> k = -94.912
Now that we have the values of k and l, we can use the equation x = ky + ly^2 to find x when y = 6:
x = (-94.912)(6) + (-22.222)(6)^2
=> x = -569.472 - 799.968
=> x = -1369.44
Therefore, when y = 6, x = -1369.44.
x varies partly as y and partly as y ^ 2When Y = 4 x = 52 * 8 and when y = 5, x = 81Find x when y = 6
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