Asked by Anonymous

x^3-36x over x^2+7x+6, divided by 6x^2-x^3 over x^2+x

I got -x as my answer, is that accurate?
Answered by Reiny
mine looked like this

x(x+6)(x-6)/[(x+1)(x-1)] x(x+1)/[x^2(6-x)]
= -1 , x no equal to 0, ±6
Answered by Anonymous
Where are you getting (x+1)(x-1)?
Answered by SIMP( secret important person)
YES BECAUSE

X^3-36X OVER X^2+7X+6,DIVIDED BY 6X^2-X^3 OVER X^2+X = X(X^2-36)OVER (6+X)(x+1, DIVIDED BY X^2(6-X)OVER X(X+1)= X(X+6)(X-6)OVER (X+6)(X+1)DIVIDED BY X^2(6-X)OVER X(X+1)= X(X-6)OVER X=1 DIVIDED BY X(X+1)OVER -X^2(-6+X)= X OVER -X WHICH EQUALS -X
Answered by Anonymous
So to clarify, was I right on the -x?
Answered by Reiny
x(x+6)(x-6)/[(x+1)(x-1)] x(x+1)/[x^2(6-x)]

should have been

x(x+6)(x-6)/[(x+1)(x+6)] x(x+1)/[x^2(6-x)] It was a transcript typo from my paper.

but still = -1
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