To solve this problem, we need to use Charles's Law, which states that the volume of a gas is directly proportional to its temperature, assuming pressure and amount of gas remain constant.
First, let's convert the Celsius temperature to Kelvin:
Celsius temperature + 273 = Kelvin temperature
So, 25 Celsius + 273 = 298 Kelvin.
Now, let's set up a proportion:
V1 / T1 = V2 / T2
Where:
V1 = initial volume = 0.852 L
T1 = initial temperature in Kelvin = 298 K
V2 = desired volume = 0.945 L
T2 = unknown temperature in Kelvin
Plugging in the known values:
0.852 / 298 = 0.945 / T2
Next, we cross-multiply and solve for T2:
0.852T2 = 0.945 * 298
0.852T2 = 281.31
T2 = 281.31 / 0.852
T2 ≈ 330.41
Therefore, the Celsius temperature necessary for the gas to have a volume of 0.945 L is approximately 330.41 - 273 = 57.41 degrees Celsius.
A sample of gas has volume of 0.852 L at 25 Celsius what Celsius temperature if necessary for the gas to have a volume of 0.945 L? Remember to use Calvin temperature at 273 to the Celsius temperature to get kelvin
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