A sample of gas has volume of 0.852 L at 25 Celsius what Celsius temperature if necessary for the gas to have a volume of 0.945 L? Remember to use Calvin temperature at 273 to the Celsius temperature to get kelvin

To solve this problem, we need to use Charles's Law, which states that the volume of a gas is directly proportional to its temperature, assuming pressure and amount of gas remain constant.

First, let's convert the Celsius temperature to Kelvin:

Celsius temperature + 273 = Kelvin temperature

So, 25 Celsius + 273 = 298 Kelvin.

Now, let's set up a proportion:

V1 / T1 = V2 / T2

Where:
V1 = initial volume = 0.852 L
T1 = initial temperature in Kelvin = 298 K
V2 = desired volume = 0.945 L
T2 = unknown temperature in Kelvin

Plugging in the known values:

0.852 / 298 = 0.945 / T2

Next, we cross-multiply and solve for T2:

0.852T2 = 0.945 * 298
0.852T2 = 281.31
T2 = 281.31 / 0.852
T2 ≈ 330.41

Therefore, the Celsius temperature necessary for the gas to have a volume of 0.945 L is approximately 330.41 - 273 = 57.41 degrees Celsius.