Question

graph the following features: slope= 2/5. Y-intercept=3

Answer 1

To graph a linear equation with a slope of 2/5 and a y-intercept of 3, we can follow these steps:

1. Start by plotting the y-intercept on the y-axis. In this case, the y-intercept is (0, 3).

2. Use the slope to find another point on the line. Since the slope is 2/5, we can interpret this as "for every 5 units moved horizontally, go up 2 units vertically." From the y-intercept, we can go 5 units to the right and 2 units up to find the second point. This gives us the point (5, 5).

Another way to find a second point is to use the slope-intercept form of the equation (y = mx + b) and plug in the values of the slope and y-intercept. In this case, the equation would be y = (2/5)x + 3. By picking any value for x, we can solve for y. Let's choose x = 5. Plugging this into the equation, we get y = (2/5)(5) + 3 = 2 + 3 = 5. So our second point is (5, 5).

3. Connect the two points (0, 3) and (5, 5) with a straight line.

Here is the graph of the line:

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6 | .
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5 | .
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4 |
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3 | .
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2 |
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1 |
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0 1 2 3 4 5 6 7 8 9 10