Asked by Algebra 2
                What's the easiest way to solve this problem
-1.28 = Sigma^-1 (25 - Mu)
1.28 = Sigma^-1 (475 - Mu)
were Sigma and Mu are each different varialbes that are constant...
Thanks
            
        -1.28 = Sigma^-1 (25 - Mu)
1.28 = Sigma^-1 (475 - Mu)
were Sigma and Mu are each different varialbes that are constant...
Thanks
Answers
                    Answered by
            MathMate
            
    Rewrite the equations as:
-1.28 =(25 - μ)/σ .... (1)
1.28 = (475 - μ)/σ .... (2)
Divide (2) by (1) to get
(475-μ)/(25-μ) = 1
Solve for μ and back substitute in (1) or (2).
μ=250, σ=175 approx.
    
-1.28 =(25 - μ)/σ .... (1)
1.28 = (475 - μ)/σ .... (2)
Divide (2) by (1) to get
(475-μ)/(25-μ) = 1
Solve for μ and back substitute in (1) or (2).
μ=250, σ=175 approx.
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