Question
Pat shows that 16 1/2 = √16. What is one possible way Pat could have shown this correctly?
16\frac{1}{2}=\left(4\cdot4\right)^{\frac{1}{2}}=4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}=4^{\frac{1}{2}}+^{\frac{1}{2}}=4^{1}=4=\sqrt{16}
16\frac{1}{2}=\left(8\cdot8\right)^{\frac{1}{2}}=8^{\frac{1}{2}}\cdot8^{\frac{1}{2}}=8^{\frac{1}{2}}+^{\frac{1}{2}}=8^{1}=8=\sqrt{16}
16\frac{1}{2}=\left(8+8\right)^{\frac{1}{2}}=8^{\frac{1}{2}}\cdot8^{\frac{1}{2}}=8^{\frac{1}{2}}+^{\frac{1}{2}}=8^{1}=8=\sqrt{16}
16\frac{1}{2}=\left(4+4\right)=4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}=4^{\frac{1}{2}}+4^{\frac{1}{2}}=4^{1}=4=\sqrt{16}
16\frac{1}{2}=\left(4\cdot4\right)^{\frac{1}{2}}=4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}=4^{\frac{1}{2}}\cdot^{\frac{1}{2}}=4^{1}=4=\sqrt{16}
16\frac{1}{2}=\left(4\cdot4\right)^{\frac{1}{2}}=4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}=4^{\frac{1}{2}}+^{\frac{1}{2}}=4^{1}=4=\sqrt{16}
16\frac{1}{2}=\left(8\cdot8\right)^{\frac{1}{2}}=8^{\frac{1}{2}}\cdot8^{\frac{1}{2}}=8^{\frac{1}{2}}+^{\frac{1}{2}}=8^{1}=8=\sqrt{16}
16\frac{1}{2}=\left(8+8\right)^{\frac{1}{2}}=8^{\frac{1}{2}}\cdot8^{\frac{1}{2}}=8^{\frac{1}{2}}+^{\frac{1}{2}}=8^{1}=8=\sqrt{16}
16\frac{1}{2}=\left(4+4\right)=4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}=4^{\frac{1}{2}}+4^{\frac{1}{2}}=4^{1}=4=\sqrt{16}
16\frac{1}{2}=\left(4\cdot4\right)^{\frac{1}{2}}=4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}=4^{\frac{1}{2}}\cdot^{\frac{1}{2}}=4^{1}=4=\sqrt{16}
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Answered by
GPT 3.5
One possible way Pat could have shown this correctly is by using the equation 16 1/2 = (4^2)^(1/2) = 4^(2*(1/2)) = 4^(1) = 4 = sqrt(16).
Answered by
GPT 3.5
One possible way Pat could have shown this correctly is by using the equation 16 1/2 = (4^2)^(1/2) = 4^(2*(1/2)) = 4^(1) = 4 = sqrt(16).
Answered by
GPT 3.5
Apologies for the confusion. One possible way Pat could have shown this correctly is by using the equation 16 1/2 = (4^2)^(1/2) = 4^(2*(1/2)) = 4^(1) = 4 = sqrt(16).
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