ms watsons recipe uses 3/4 cup of milk to make 12 biscuits how many cups of milk will be used to make 36 biscuits

11 answers

If Ms. Watson's recipe uses 3/4 cup of milk to make 12 biscuits, we can set up a ratio to find out how much milk is needed for 36 biscuits.

3/4 cup of milk is used for 12 biscuits.

Therefore, 1 cup of milk is used for (12/3/4) * 1 = 16 biscuits.

To find out how much milk is needed for 36 biscuits, we can set up a proportion.

1 cup of milk is used for 16 biscuits.

x cups of milk is used for 36 biscuits.

1/16 = x/36.

We can cross-multiply:

36 = 16x.

Divide both sides by 16:

x = 36/16 = 9/4 = 2 1/4.

Therefore, to make 36 biscuits, 2 1/4 cups of milk will be used.
Rectangles M and N are similar. Each side of rectangle M is five times longer than the corresponding side of rectangle N. What is the ratio of the perimeter of rectangle M to the perimeter of rectangle N?
Let's assume the length of each side of rectangle N is "x".

According to the given information, each side of rectangle M is five times longer than the corresponding side of rectangle N. Therefore, the length of each side of rectangle M is 5x.

The perimeter of a rectangle can be calculated by adding the lengths of all its sides.

The perimeter of rectangle N = x + x + x + x = 4x

The perimeter of rectangle M = 5x + 5x + 5x + 5x = 20x

To find the ratio of the perimeter of rectangle M to the perimeter of rectangle N, we divide the perimeter of rectangle M by the perimeter of rectangle N:

(Perimeter of rectangle M) / (Perimeter of rectangle N) = 20x / 4x = 20 / 4 = 5.

Therefore, the ratio of the perimeter of rectangle M to the perimeter of rectangle N is 5:1.
A sandbox is 2.5 m wide and 3.4 m long . approximately how much sand will it take to fill it 0.3 m deep?
To find out how much sand is needed to fill the sandbox, we can calculate the volume of the sandbox.

The volume of a rectangular prism (such as the sandbox) is given by the formula: volume = length x width x height.

In this case, the length of the sandbox is 3.4 m, the width is 2.5 m, and the depth or height is 0.3 m.

So, the volume of sand needed to fill the sandbox is: volume = 3.4 m x 2.5 m x 0.3 m = 2.55 cubic meters.

Therefore, approximately 2.55 cubic meters of sand will be needed to fill the sandbox to a depth of 0.3 m.
a circle has an area of 144 pi cm^2. find the circumference
The formula to find the area of a circle is:

Area = π * r^2

Given that the area of the circle is 144π cm², we can set up the equation:

144π = π * r^2

To find the radius, we divide both sides of the equation by π:

144 = r^2

Taking the square root of both sides, we get:

r = √144

r = 12

Therefore, the radius of the circle is 12 cm.

To find the circumference of the circle, we use the formula:

Circumference = 2 * π * r

Circumference = 2 * π * 12

Circumference = 24π

Thus, the circumference of the circle is 24π cm or approximately 75.4 cm.
The list shows the weight of some packages in pounds. The data will be put in a line plot. 3/8 , 1/2 , 7/8 , 3/4 , 1/4 , 1/2 , 3/4 Drag numbers to the blanks to make the sentence true. __ The scale for the line plot should be t with tick marks at every_ 0 1 2 1/8 1/4 1/2
The scale for the line plot should be _t_ with tick marks at every _1/8_, _1/4_, _1/2_.

The numbers that fit the statement and are present in the list are:
- 1/8
- 1/4
- 1/2
The right triangle P Q R is shown. P has coordinates (negative 5, 4). Q has coordinates (3, 4). R has coordinates (3, negative 4).QuestionA dilation image of triangle P Q R with a scale factor 4 and center at the origin is drawn. The image is triangle P prime Q prime R prime. What is the ratio of the length of segment P prime Q prime to the length of segment Q prime R prime?Answer options with 4 options
A.1 colon 1

B.4 colon 1

C.8 colon 1

D.16 colon 1
To find the ratio of the length of segment P'Q' to the length of segment Q'R' in the dilation image, we need to calculate the distances between the corresponding points.

First, let's find the coordinates of the dilated triangle P'Q'R':
P' = (4 × (-5), 4 × 4) = (-20, 16)
Q' = (4 × 3, 4 × 4) = (12, 16)
R' = (4 × 3, 4 × (-4)) = (12, -16)

Now let's find the lengths of the line segments:
Length of segment P'Q' = √[(12 - (-20))^2 + (16 - 16)^2] = √[32^2 + 0^2] = 32
Length of segment Q'R' = √[(12 - 12)^2 + (-16 - 16)^2] = √[0^2 + (-32)^2] = 32

The ratio of the length of segment P'Q' to the length of segment Q'R' is therefore:
P'Q' : Q'R' = 32 : 32 = 1 : 1

Therefore, the correct answer option is A. 1 : 1.