5(8−6b)−5(2−3b)=−60

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1 answer

To solve this equation, we can distribute the numbers outside the parentheses to the expressions inside the parentheses.

For the first set of parentheses, we have 5(8−6b). Distributing 5, we get:

5 * 8 - 5 * 6b

= 40 - 30b

For the second set of parentheses, we have 5(2−3b). Distributing 5, we get:

5 * 2 - 5 * 3b

= 10 - 15b

Now our equation looks like:

(40 - 30b) - (10 - 15b) = -60

Next, we can remove the parentheses:

40 - 30b - 10 + 15b = -60

Combining like terms:

(40 - 10) + (-30b + 15b) = -60

30 + (-15b) = -60

Now we can combine the positive and negative 15b terms:

30 - 15b = -60

To solve for b, we can isolate the variable by moving the constant to the other side of the equation.

Subtracting 30 from both sides:

30 - 30 - 15b = -60 - 30

-15b = -90

Finally, we can solve for b by dividing both sides by -15:

-15b / -15 = -90 / -15

b = 6