Let's represent time with the variable "t".
The first vat is empty and being filled at a rate of 6 gallons per minute. Therefore, the amount of liquid in the first vat after "t" minutes is given by: 6t.
The second vat already contains 28 gallons and is being filled at a rate of 4 gallons per minute. Therefore, the amount of liquid in the second vat after "t" minutes is given by: 28 + 4t.
To find the time when the two vats have the same amount of liquid, we need to set the expressions for the two vats equal to each other and solve for "t":
6t = 28 + 4t
Subtracting 4t from both sides:
2t = 28
Dividing both sides by 2:
t = 14
Therefore, the two vats will have the same amount of liquid after 14 minutes. Answer: \boxed{14}.
Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other vat already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. When will the two vats have the same amount of liquid?(1 point)
They will have the same amount of liquid after blank
minutes.
1 answer