Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)

Question

Responses

92+16x=104+13x ; x=4
92 plus 16 x equals 104 plus 13 x ; x equals 4

92−16x=104−13x ; x=−4
92 minus 16 x equals 104 minus 13 x ; x equals negative 4

104+16x=92+13x ; x=4
104 plus 16 x equals 92 plus 13 x ; x equals 4

92+16x=104+13x ; x=6

Answer 1

The correct equation is 92+16x=104+13x, where x represents the number of minutes.

To solve the equation, we will isolate the variable x on one side of the equation.

Subtract 13x from both sides:

92+16x-13x=104

Combine like terms:

92+3x=104

Subtract 92 from both sides:

3x=12

Divide both sides by 3:

x=4

Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.