The equation of a line can be written in the form y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is -2 and the point (3, 5) lies on the line, we can substitute these values into the equation and solve for b.
5 = -2(3) + b
5 = -6 + b
b = 5 + 6
b = 11
Therefore, the equation of the line is y = -2x + 11.
Find an equation of the line having the given slope and containing the given point.
m = -2, (3,5)
1 answer
1 answer