Asked by Amelie
I had to factor 5x^3-10x^2+43x-6. I got 5x(x^2+-2x)+3(x-2). My teacher said this was half right. What did I do wrong then? Thank you!!
Answers
Answered by
Danialle
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Answered by
MathMate
Your answer expands to
5*x^3-10*x^2+3*x-6
Could you check the question if the coefficient is not 3x instead of 43x.
The expression as in the qustion has no rational factors, so there is probably a typo somewhere.
Yes, your answer is half-way, if not more, to factorizing completely.
5*x^3-10*x^2+3*x-6
Could you check the question if the coefficient is not 3x instead of 43x.
The expression as in the qustion has no rational factors, so there is probably a typo somewhere.
Yes, your answer is half-way, if not more, to factorizing completely.
Answered by
Amelie
Yes, it is supposed to be a three, not a fourty three.
Answered by
MathMate
If it is a 3x and not 43x, then you only have to continue your factorization:
5x(x^2+-2x)+3(x-2)
=5x(x^2-2x)+3(x-2)
=5x²(x-2) + 3(x-2)
=(5x²+3)(x-2)
which is the correct answer.
Check:
(5x²+3)(x-2)
=5x³ -10² + 3x -6 OK
5x(x^2+-2x)+3(x-2)
=5x(x^2-2x)+3(x-2)
=5x²(x-2) + 3(x-2)
=(5x²+3)(x-2)
which is the correct answer.
Check:
(5x²+3)(x-2)
=5x³ -10² + 3x -6 OK
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