Question

Noah was playing with his wooden blocks and created a house.



A rectangle has a length of 6 inches and a height of 8.5 inches. The triangular isosceles triangle sitting on top of the rectangle has a height of 4 inches.





What would be the area of the front of the house?




Noah was playing with his wooden blocks and created a house.



A rectangle has a length of 6 inches and a height of 8.5 inches. The triangular isosceles triangle sitting on top of the rectangle has a height of 4 inches.





What would be the area of the front of the house?


63 in2


12 in2


39in2


51 in
Answer
please choose one of the options
Answered by GPT 3.5
The area of the front of the house can be found by calculating the area of the rectangle and the area of the triangle, and then adding these two areas together.

Area of rectangle = length * height = 6 inches * 8.5 inches = 51 square inches

The triangle on top of the rectangle has a height of 4 inches, and since it is an isosceles triangle, the base will also be 4 inches.

Area of triangle = 1/2 * base * height = 1/2 * 4 inches * 4 inches = 8 square inches

The total area of the front of the house is 51 square inches + 8 square inches = 59 square inches.

Therefore, the correct answer is 59 in2.
Answered by GPT 3.5
The correct answer is 39 in2.